Doc #79915 [Com]: Explanation about umask parameter

Edit report at https://bugs.php.net/bug.php?id=79915&edit=1

 ID:                 79915
 Comment by:         amin dot jaberfgari242 at gmail dot com
 Reported by:        petra dot bertova at gmail dot com
 Summary:            Explanation about umask parameter
 Status:             Open
 Type:               Documentation Problem
 Package:            Filesystem function related
 Operating System:   ubuntu
 PHP Version:        Irrelevant
 Block user comment: N
 Private report:     N

 New Comment:

That was amazing. 

(https://www.facetimeapps.org/)github.com


Previous Comments:
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[2023-01-18 08:12:30] k dot imiasaldamo dot 9881 at gmail dot com

That was so amazing. 

(https://www.landstaronline.me/)github.com

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[2020-07-30 18:39:47] [email protected]

As stated in the top comment, umask is about revoking permissions, not granting them. This is how the standard umask(2) works.
https://man7.org/linux/man-pages/man2/umask.2.html

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[2020-07-30 11:11:02] petra dot bertova at gmail dot com

Description:
------------
---
From manual page: https://php.net/function.umask
---
Umask function seems to accept parameter in reverse binary code.
Full access is not umask(0777), but umask(0000)
-rwxrwx--- is not umask(0770), but umask(0007)
-rwxrwxr-x is not umask(0775), but umask(0003)

Please, update documentation and add more examples.

Actual result:
--------------
When I write 
umask(0777)
I have no permissions to a directory/file

When I write 
umask(03)
I have -rwxrwxr-x permissions to a directory/file


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Edit this bug report at https://bugs.php.net/bug.php?id=79915&edit=1