Re: [PHP] Re: british date format

André Medeiros wrote:
> Yeah, that would be the way to do it ;)
> 
> On Fri, May 9, 2008 at 3:54 PM, Shawn McKenzie <[email protected]> wrote:
>> Shawn McKenzie wrote:
>>> André Medeiros wrote:
>>>> Shawn,
>>>>
>>>> I think the idea here was to get a timestamp from a date in that
>>>> format he was telling about.
>>>>
>>>> After replying however, I noticed that strptime is only implemented in
>>>> PHP5. Sorry about that mate.
>>>>
>>>> On Fri, May 9, 2008 at 2:36 PM, Shawn McKenzie <[email protected]>
>>>> wrote:
>>>>> Merca, Ansta Ltd wrote:
>>>>>> Hi
>>>>>>
>>>>>> Anyone "dd/mm/yyyy" as a date variable? strtotime - works fine with
>>>>>> "mm/dd/yyyy" but now with "dd/mm/yyyy". (PHP 4.x)
>>>>> setlocale()
>>>>>
>>>>> and then...
>>>>>
>>>>> http://pt.php.net/manual/en/function.strftime.php
>>>>>
>>>>> -Shawn
>>>>>
>>>>> --
>>>>> PHP General Mailing List (http://www.php.net/)
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>>>>>
>>>>>
>>> Couldn't see any other way.  *nix strtotime is supposed to use locale.
>>>
>> Fixed that for me:
>>
>> $date = '20/12/1971';
>> $d = explode('/', $date);
>> echo mktime(0 ,0, 0, $d[1], $d[0],$d[2])."\n";
>>
>>> -Shawn
>> --
>> PHP General Mailing List (http://www.php.net/)
>> To unsubscribe, visit: http://www.php.net/unsub.php
>>
>>

I was bored.  Just an example, and I named it _eur because I assume that 
all European dates are this way, but some may have a / or a - or . 
separator.  intval() is to remove preceding 0 or it is treated as octal.

<?php

function strtotime_eur($date)
{
     preg_match('|([0-9]{1,2})[/.-]([0-9]{1,2})[/.-]([0-9]{2,4})|',
		$date, $parts);

     if(count($parts) != 4) {
         return false;
     }
     $d = intval($parts[1]);
     $m = intval($parts[2]);
     $y = intval($parts[3]);

     return mktime(0 ,0, 0, $m, $d, $y);
}

?>

-Shawn