Re: [PHP] array conversion

Or,

function new_arr(array $arr)
{
    $count = count($arr);
    if ($count % 2 != 0) throw new Exception('The new_arr() function
requires an even number of elements.');
    for ($i = 0; $i < $count; $i += 2)
    {
        $new_arr[$arr[$i]] = $arr[$i + 1];
    }
    return $new_arr;
}

$test = new_arr(array('k1', 'v1', 'k2', 'v2', 'k3', 'v3'));

exit(var_dump($test));

On Fri, Feb 19, 2010 at 1:19 AM, Larry Garfield <[email protected]>wrote:

> On Thursday 18 February 2010 11:58:28 pm Paul M Foster wrote:
> > On Fri, Feb 19, 2010 at 01:20:12PM +0800, Dasn wrote:
> > > Hi guys. How to convert an array like:
> > >
> > > Array
> > > (
> > >     [0] => key1
> > >     [1] => value1
> > >     [2] => key2
> > >     [3] => value2
> > > )
> > >
> > > to
> > >
> > >
> > > Array
> > > (
> > >     [key1] => value1
> > >     [key2] => value2
> > > )
> > >
> > > Is there a built-in function to do this?
> > > Please Cc me. :)
> > > Thank you in advance.
> >
> > I don't believe so, but rolling your own should not be too hard:
> >
> > $a = array($key1, $value1, $key2, $value2);
> > $b = array();
> > $numitems = count($a);
> >
> > for ($i = 0; $i < $numitems; $i++) {
> >       if ($i % 2 == 0) {
> >               $saved_key = $a[$i];
> >       }
> >       elseif ($i % 2 == 1) {
> >               $b[$saved_key] = $a[$i];
> >       }
> > }
> >
> > Code is crude and untested, but you get the idea.
> >
> > Paul
>
> This would be even shorter, I think:
>
> foreach ($items as $i => $value) {
>  $temp[$i % 2][] = $value;
> }
> $done = array_combine($temp[0], $temp[1]);
>
> (Also untested, just off the cuff...)
>
> --Larry Garfield
>
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>


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