Re: [PHP] array conversion

On 19 February 2010 07:26, Adam Richardson <[email protected]> wrote:
> Or,
>
> function new_arr(array $arr)
> {
>    $count = count($arr);
>    if ($count % 2 != 0) throw new Exception('The new_arr() function
> requires an even number of elements.');
>    for ($i = 0; $i < $count; $i += 2)
>    {
>        $new_arr[$arr[$i]] = $arr[$i + 1];
>    }
>    return $new_arr;
> }
>
> $test = new_arr(array('k1', 'v1', 'k2', 'v2', 'k3', 'v3'));
>
> exit(var_dump($test));
>
> On Fri, Feb 19, 2010 at 1:19 AM, Larry Garfield <[email protected]>wrote:
>
>> On Thursday 18 February 2010 11:58:28 pm Paul M Foster wrote:
>> > On Fri, Feb 19, 2010 at 01:20:12PM +0800, Dasn wrote:
>> > > Hi guys. How to convert an array like:
>> > >
>> > > Array
>> > > (
>> > >     [0] => key1
>> > >     [1] => value1
>> > >     [2] => key2
>> > >     [3] => value2
>> > > )
>> > >
>> > > to
>> > >
>> > >
>> > > Array
>> > > (
>> > >     [key1] => value1
>> > >     [key2] => value2
>> > > )
>> > >
>> > > Is there a built-in function to do this?
>> > > Please Cc me. :)
>> > > Thank you in advance.
>> >
>> > I don't believe so, but rolling your own should not be too hard:
>> >
>> > $a = array($key1, $value1, $key2, $value2);
>> > $b = array();
>> > $numitems = count($a);
>> >
>> > for ($i = 0; $i < $numitems; $i++) {
>> >       if ($i % 2 == 0) {
>> >               $saved_key = $a[$i];
>> >       }
>> >       elseif ($i % 2 == 1) {
>> >               $b[$saved_key] = $a[$i];
>> >       }
>> > }
>> >
>> > Code is crude and untested, but you get the idea.
>> >
>> > Paul
>>
>> This would be even shorter, I think:
>>
>> foreach ($items as $i => $value) {
>>  $temp[$i % 2][] = $value;
>> }
>> $done = array_combine($temp[0], $temp[1]);
>>
>> (Also untested, just off the cuff...)
>>
>> --Larry Garfield
>>
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>>
>>
>

I'd say that this cat is well and truly skinned!
>
> --
> Nephtali:  PHP web framework that functions beautifully
> http://nephtaliproject.com
>



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