Re: [PHP] PHP Syntax Help - Check?
[email protected] (Rick Dwyer)
| Newsgroups | php.general |
|---|---|
| Message-ID | <[email protected]> |
Hmm. OK with the help below, I am closer.
The other fields on the page are getting passed via form fields that
look like this:
input type="text" value="<?php echo check('element9'); ?>"
name="form[element9]" size="40" maxlength="255"
so I added:
input type="text" value="<?php echo check('my_id'); ?>"
name="form[my_id]" size="40" maxlength="255"
and formcheck.php has:
<?php
//start the session
session_start();
//array of fields in form. (In the format "field_name" => "field_label")
$form_fields = array(
"element0" => 'Your Name:',
"element1" => 'Your Email:',
"element4" => 'Item Number:',
.....
);
and I added:
"my_id" => 'My ID Is:',
And this works!
So when I am on mypage.php and I enter a value into the form field
"my_id" it carries over and repopulates should the form fail validation.
But upon initial load of the page from my link of mypage.php?my_id=5
(so I am not getting there via a form submit) how do I get the value
into the form field?
--Rick
On Feb 25, 2010, at 1:02 AM, viraj wrote:
> if you do the redirection with header('Location: /mypage.php'),
> setting a variable on formcheck.php is not enough.
>
> if you modify the header('Location: /mypage.php') to..
>
> header('Location: /mypage.php?my_id=5')
>
> it will take the variable to mypage.php as $_GET['my_id]
>
> you can not expect a variable value set in to $_POST array to reflect
> on a totally different page without making it a form post (aka use of
> proper headers).
>
> i guess, it's time to you to read about session_start() method and the
> array $_SESSION available in php :)
>
>
> ~viraj
>
> On Thu, Feb 25, 2010 at 11:22 AM, Rick Dwyer <[email protected]>
> wrote:
>> OK... external function... that would explain why I could not
>> locate it.
>>
>> Let me get right to the problem I am having with this code as
>> someone may be
>> able to help directly.
>>
>> I have a link on a page that opens a contact form. The link is
>> mypage.php?my_id=5
>>
>> So on mypage.php, I capture this value with:
>> $my_id=$_GET['my_id'];
>>
>> I understand this much. But when the end user submits this contact
>> form
>> they do so to formcheck.php and if formcheck.php sees a required
>> field is
>> blank, it throws it back to mypage.php with an alert. BUT, I lose
>> the value
>> of the variable $my_id. SO, I created a hidden field on mypate.php
>> with
>> value="<?php echo $my_id; ?>" and on formcheck.php, I added $my_id =
>> $_Post['my_id'];
>>
>> However, when formcheck.php returns me to mypage.php, $my_id is
>> still blank.
>>
>> Very frustrating.
>>
>> Any help determining what I am doing wrong is greatly appreciated.
>>
>> Thanks.
>>
>>
>>
>> --Rick
>>
>>
>> On Feb 25, 2010, at 12:31 AM, Paul M Foster wrote:
>>
>>> On Thu, Feb 25, 2010 at 12:16:08AM -0500, Robert Cummings wrote:
>>>
>>>> Rick Dwyer wrote:
>>>>>
>>>>> Hello all.
>>>>>
>>>>> I'm trying to learn PHP on the fly and I have a line of code that
>>>>> contains syntax I can't find documented anywhere:
>>>>>
>>>>> php echo check('element8');
>>>>>
>>>>> In the above line, can someone tell me what "check" means?
>>>>
>>>>
>>>> In the above, check is a function. It is being called with
>>>> parameter
>>>> 'element8'.
>>>
>>> This is true. But perhaps more importantly, check() is not a
>>> native PHP
>>> function. Thus it comes from some other library or group of external
>>> functions.
>>>
>>> Paul
>>>
>>> --
>>> Paul M. Foster
>>>
>>> --
>>> PHP General Mailing List (http://www.php.net/)
>>> To unsubscribe, visit: http://www.php.net/unsub.php
>>>
>>
>>
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>>
>
>
>
> --
> ~viraj
>
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