Re: [PHP] Execution order of PHP

Bruno Fajardo wrote:
> 2010/3/10 Auke van Slooten <[email protected]>
>> Hi,
>>
>> In a hobby project I'm relying on the order in which the following piece of PHP code is executed:
>>
>> $client->system->multiCall(
>>  $client->methodOne(),
>>  $client->methodTwo()
>> );
> 
> Can't you call the methods $client->methodOne() and
> $client->methodTwo() before the call to $client->system->multiCall()?
> That way, you could store they values in local variables, and then
> pass them to the $client->system->multiCall(), assuring that those
> methods are executed before the multiCall(). Something like:
> 
> $methodOne = $client->methodOne();
> $methodTwo = $client->methodTwo();
> $client->system->multiCall($methodOne, $methodTwo);

Hi,

This is not what I meant. I should perhaps mention that it's an xml-rpc 
client and the method calls are remote method calls. The multiCall 
method gathers multiple method calls into a single request.

The trick I'm using now is to set a private property in the 
$client->__get() method when the property you're accessing is 'system'. 
 From then untill you call the method 'multiCall', instead of calling 
the methods (in this case methodOne and methodTwo) the client creates a 
new object with the call information (method name and arguments) and 
returns that. In multiCall all arguments are therefor call information 
objects and multicall creates a single request based on that information.

So in your example the client would simply call methodOne and methodTwo 
and return the results. Then it would try to do a multiCall with 
whatever the previous methods have returned.

regards,
Auke van Slooten
Muze