Array help.

I have a query that may not always return a result for a value, I need
to reflect this with a "0". I am trying to overcome this by doing this
(the keys are ID's):

while ($row = mysql_fetch_row($statusQuery)) {

        $cat = array(0=>0,1=>0,11=>0,12=>0,13=>0,14=>0,15=>0,16=>0,17=>0,19=>0);

        switch ($row[1]) {
            case 0: $cat[0] = $row[0]; break;
            case 1: $cat[1] = $row[0]; break;
            case 11: $cat[11] = $row[0]; break;
            case 12: $cat[12] = $row[0]; break;
            case 13: $cat[13] = $row[0]; break;
            case 14: $cat[14] = $row[0]; break;
            case 15: $cat[15] = $row[0]; break;
            case 16: $cat[16] = $row[0]; break;
            case 17: $cat[17] = $row[0]; break;
            case 19: $cat[19] = $row[0]; break;
        }

        print_r($cat);
    }

Which gives me this:

Array ( [0] => 15547 [1] => 0 [11] => 0 [12] => 0 [13] => 0 [14] => 0
[15] => 0 [16] => 0 [17] => 0 [19] => 0 )
Array ( [0] => 0 [1] => 0 [11] => 0 [12] => 0 [13] => 0 [14] => 0 [15]
=> 30 [16] => 0 [17] => 0 [19] => 0 )

The query only return 2 rows:

15 | 30
0 | 15547

What am I doing wrong? Is there a more elegant way to achieve what I want?

Thanks.

-- 
Paul Halliday
Ideation | Individualization | Learner | Achiever | Analytical
http://www.pintumbler.org