Re: [PHP] mysql_connect noob question
[email protected] (Glob Design Info)
| Newsgroups | php.general |
|---|---|
| Message-ID | <[email protected]> |
Even more strange: It doesn't work from the form with or without the domain (but on the command line it does), but...... IF I add the $_REQUEST access *and* use the user that the *MySQL* install has, and *not* the xeround user name (my email), then it *does* work! WEIRD. On 4/21/13 3:59 PM, David OBrien wrote: > In fact using the @gmail.com part added on gives me the same error as the OP > I think their welcome email needs tweaking.. try it without the domain > added on > > > On Sun, Apr 21, 2013 at 6:56 PM, David OBrien <[email protected]> wrote: > >>> I should note my user name in this case *is* an email address, however >> the dots in that address are *not* being converted to underscores as >> mentioned (at least not visibly). >> >> >> I just created a free account there and the email says my username is >> [email protected] >> but I connected to it from sqlyog and a php page by using JUST "dgobrien" >> >> <?php >> $host = "instance44364.db.xeround.com:3924"; >> >> if ( $_REQUEST['Submit'] ) { >> $conn = mysql_connect( $host, $_REQUEST['username'], $_REQUEST['password'] >> ) or die( mysql_error() ); >> if ($conn) { >> mysql_select_db("uwharrie") or die( mysql_error() ); >> echo "Connected<br>"; >> } >> } >> >> ?><form id='login' action='index.php' method='post' accept-charset='UTF-8'> >> <legend>Login</legend> >> <input type='hidden' name='submitted' id='submitted' value='1'/> >> <label for='username' >UserName*:</label> >> <input type='text' name='username' id='username' value='dgobrien' >> maxlength="50" /> >> <label for='password' >Password*:</label> >> <input type='password' name='password' id='password' maxlength="50" >> value='mmmmmm' /> >> <input type='submit' name='Submit' value='Submit' /> >> </form> >>