Re: [PHP] Split/Group date together.

Normally, what I do here is handle that in the loop to display the records
... so start by adding an order by clause to keep the dates together

SELECT * FROM transportdokument WHERE dato >= '16/7/2013' AND dato
<= '18/7/2013' order by dato

$prior_date = "";

$sHTML = "<table>";

while($rows = mysql_fetch_array($result)){

    if ($prior_date != $rows['dato']){
        if($open_table){
           $sHTML .= "</table><table>";
           $prior_date = $rows['dato'];
         }
    }
    $sHTML .= "<tr>";
    $sHTML .= "<td>". $rows['dato'] . "</td>";
    $sHTML .= "<td>". $rows['some_field'] . "</td>";
    $sHTML .= "<td>". $rows['another_field'] . "</td>";
    $sHTML .= "<td>". $rows['third_field'] . "</td>";
    $sHTML .= "</tr>";
}

$sHTML .= "</table>";


On Thu, Jul 18, 2013 at 9:43 AM, Karl-Arne Gjersøyen <[email protected]>wrote:

> Hello again.
> In my program I have this:
>
> mysql> SELECT * FROM transportdokument WHERE dato >= '16/7/2013' AND dato
> <= '18/7/2013';
>
> This list all reccrds for 3 days. I need a way to split it up for every day
> even when the requst is as above and don't know in what way I can do it.
>
> I like to have all records for day 16 in one table in PHP/HTML and all
> records for day 17 in another table.
> i.e, Day 16 have 5 rows and day 17th and 18th have 7 and 8 rows.
>
> I hope for your help and advice to do also this correct.
>
> Thank you for your time and effort!
>
> Karl
>



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