Re: [PHP] Resolving a PHP Notice Error

2013/9/17 Ron Piggott <[email protected]>

>
> I am wanting to establish a default sort by preference when the user
> hasn’t specified one.  I setup to test this with:
>
> <?php
>
> if ( !is_set( $sort_by_preference ) ) {
>
>     $sort_by_preference = "government_wording";
>
> }
>
> ?>
>
> But I am receiving a Notice error:
>
> Notice:  Undefined variable: sort_by_preference in GIFI_codes.php on line
> 11- Line 11 is “if ( !is_set( $sort_by_preference ) ) {“What is the correct
> way to test this without triggering a Notice error?Ron
> Ron Piggott
>

Because actually you are looking for isset() (not is_set()).


>
>
>
> www.TheVerseOfTheDay.info
>



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