Re: [PHP] header() not working?
[email protected] (Ryan Pallas)
| Newsgroups | php.general |
|---|---|
| Message-ID | <CAObuZdsmh2YfA-VXvA4_7cZeRBRNX4_2UBBHexHVkOx=V8nkPg@mail.gmail.com> |
On Sat, Dec 10, 2016 at 8:22 AM, Tedd Sperling <[email protected]> wrote: > > > On Dec 8, 2016, at 1:05 PM, Christoph M. Becker <[email protected]> > wrote: > > > > On 08.12.2016 at 18:53, Ryan Pallas wrote: > > > >> On Thu, Dec 8, 2016 at 10:40 AM, Christoph M. Becker <[email protected] > > > >> wrote: > >> > >>> On 08.12.2016 at 17:30, Tedd Sperling wrote: > >>> > >>>> For several years I have had an example of a redirect working on my > >>> college’s Server for my students to review. > >>>> > >>>> The code is simple: > >>>> > >>>> header ("Location:$where"); > >>>> exit(0); > >>>> > >>>> -snip- > > > > Good catch! Note, however, that RFC 7231 which obsoletes RFC 2616 has > > relaxed this: > > > > Location = URI-reference > > > > Still, `amazon.com` would not be valid according to the spec. > > > > Cheers, > > Christoph > > > >> [1] - https://www.w3.org/Protocols/rfc2616/rfc2616-sec14.html#sec14.30 > >> [2] - https://www.w3.org/Protocols/HTTP/1.0/spec.html#URI > > Thanks. > > Good consideration, but that’s not the problem. > > Here’s the URL and code, try it yourself: > > http://citw.lcc.edu/~sperlt/citw185/examples/redirect.php You have output before header call. If you turned on error_reporting ike Chris mentioned, you would see that output had already started. Specifically this line is output: print_r($_POST); > > > Cheers, > > tedd > > _______________ > tedd sperling > [email protected] > > > > > >