Re: In php 8.0: unable to distinguish between instance variable beingnull and unset

Was missing a ? there. Updated case at
https://3v4l.org/rH4p4

On Sat, 4 Sep 2021 at 21:30, Ben Ramsey <[email protected]> wrote:

> Emiel Mols wrote on 9/3/21 07:08:
> > Hello,
> >
> > Our codebase depends on distinguishing whether an instance variable is
> > unset, or simply null:
> >
> > class C { public int $v = 123; }
> > $x = new C; unset($x->v);
> > $y = new C; $u->v = null;
> >
> > In php <8.0 we made this work with @array_key_exists($x, 'v'), which
> > stopped working. isset($x->x) doesn't work, as it will return true for
> > 'null' as well. property_exists($x, 'v') will always return true as long
> as
> > the variable is declared: php-src here
> > <
> https://github.com/php/php-src/blob/a13730c5e465b3c349a7970d15a49e4e132d4e07/Zend/zend_builtin_functions.c#L943
> >
> > .
> >
> > Apart from using debug_zval_dump (too expensive), any hints? This feels
> > like quite the oversight honestly :).
> >
> > Best,
> >
> > Emiel
> >
>
> If you use `public int $v`, there shouldn't be a way to set it `null`,
> unless I'm missing something.
>
> https://3v4l.org/nNDq4
>
> Cheers,
> Ben
>
>