Re: [PHP-DEV] [RFC] Pipe Assignment Operator

Hi

On 2026-07-13 21:02, Caleb White wrote:
>> The only thing I'm missing for the semantics is an explicit 
>> explanation
>> of the operator precedence and associativity (it has the same 
>> precedence
>> and associativity as any other assignment operator; but this needs to 
>> be
>> in the RFC). And please also include explicit examples along the lines
>> of:
>> 
>> If you write `$foo |>= bar(...) |> baz(...)` it will be interpreted as
>> if you have written `$foo = (($foo |> bar(...)) |> baz(...))` with the
>> very explicit redundant parentheses.
>> 
>> Please also include some additional more complex examples, e.g. `$foo
>> |>= $bar |>= …`, `$foo += $bar |>= …` and similar to make sure there 
>> is
>> no ambiguity for possible use cases that users might have.
> 
> I've added a section in the RFC for this and included more complex 
> examples.

Thank you. One note regarding “the lowest precedence level, 
right-associative”. This is not quite correct. While the assignment 
operators have fairly low precedence, they are not the lowest. As an 
example, the infamous `$foo = bar() or die()` pattern relies on `or` 
having a lower precedence than assignment. This should be corrected.

The `$result = ($x |>= double(...)) |> triple(...);` example also 
doesn't showcase precedence, because of the explicit parentheses.

------

Looking at the RFC examples again, I was reminded of this RFC: 
https://wiki.php.net/rfc/implicit_move_optimisation, which concerns 
itself with optimizing the `$foo = func($foo);` case. Perhaps it makes 
sense to list this in the references section, because with `|>=` this 
“in-place” reassignment would become an official pattern.

Best regards
Tim Düsterhus