note 98040 deleted from function.json-encode by derick

Note Submitter: spansjh at nospam dot gmail dot com 

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The function json_encode does not return the JSON code in 'human-readable' formats. The function below will format any JSON code given to it.

<?php
function json_format($input){
	$tab = 0;
	$out = "";
	$tabs = "";
	for($i=0;$i<strlen($input);$i++){
		$c = $input[$i];
		$tabs = "";
		for($t=1;$t<=$tab;$t++)
			$tabs .= "\t";
		switch($c){
			case "{":
				$tab++;
				$tabs .= "\t";
				$out .= "{\n".$tabs;
				break;
			case "}":
				$tab--;
				$tabs[strlen($tabs)-1] = "";
				$out .= "\n".$tabs."}";
				break;
			case "[":
				$tab++;
				$tabs .= "\t";
				$out .= "[\n".$tabs;
				break;
			case "]":
				$tab--;
				$tabs[strlen($tabs)-1] = "";
				$out .= "\n".$tabs."]";
				break;
			case ",": $out .= ",\n".$tabs; break;
			default: $out .= $c; break;
		}
	}
	$out = str_replace("\x00", "", $out);
	return $out;
}
?>

Example:

<?php
$a = array("Name"=>"Angelo","Age"=>16,
      "Interests"=>array("Games","Television","Holidays"));
echo json_format(json_encode($a));
?>

This will output:

{
        "Name":"Angelo",
        "Age":16,
        "Interests":[
                "Games",
                "Television",
                "Holidays"
        ]
}