Enhancement Request

[email protected] (Szii) Tue, 30 May 2000 23:02:57 -0700
Newsgroups php.version4
Message-ID <[email protected]>
Application: Pulling .jpg files out of a database into the in-memory file and
then exported directly to the html.

Workarounds:
	1) Not putting image files in the database
	2) Export to a temp file and use <img src=x.jpg>
	3) Separate .php file using header(image/jpg)
                and use <img src=xxx.php?id=y>

Just wishing for a "clean solution."  Best bet so far is just calling an
external php file with ? params.  Wish I could just call one of my
classes member methods to load/dump it instead of having to hack
my way with external files.  1 4line snippet of code for a whole file
gets kinda annoying.

I can put it in the DB, get it out, but it's becoming a PITA to display it 
properly.  Maybe someone can suggest a workaround?

-Szii

An another note:

  print "<img src=\"$ad->OutputPhoto($cat,$valObject->AdID)\">";
  echo $ad->OutputPhoto($cat,$valObject->AdID);
  print "$ad->OutputPhoto($cat,$valObject->AdID)";

The first "print" call says UndefinedProperty: OutputPhoto
The "echo" call works as expected.
The second "print" call works as expected.

Can anyone explain why being inside the <img src=> tag would cause
it to become an undefined property?