Enhancement Request
[email protected] (Szii) Tue, 30 May 2000 23:02:57 -0700
| Newsgroups | php.version4 |
|---|---|
| Message-ID | <[email protected]> |
Application: Pulling .jpg files out of a database into the in-memory file and
then exported directly to the html.
Workarounds:
1) Not putting image files in the database
2) Export to a temp file and use <img src=x.jpg>
3) Separate .php file using header(image/jpg)
and use <img src=xxx.php?id=y>
Just wishing for a "clean solution." Best bet so far is just calling an
external php file with ? params. Wish I could just call one of my
classes member methods to load/dump it instead of having to hack
my way with external files. 1 4line snippet of code for a whole file
gets kinda annoying.
I can put it in the DB, get it out, but it's becoming a PITA to display it
properly. Maybe someone can suggest a workaround?
-Szii
An another note:
print "<img src=\"$ad->OutputPhoto($cat,$valObject->AdID)\">";
echo $ad->OutputPhoto($cat,$valObject->AdID);
print "$ad->OutputPhoto($cat,$valObject->AdID)";
The first "print" call says UndefinedProperty: OutputPhoto
The "echo" call works as expected.
The second "print" call works as expected.
Can anyone explain why being inside the <img src=> tag would cause
it to become an undefined property?