Re: [RFC] tools/memory-model: Rule out OOTA

On Mon, Jan 06, 2025 at 10:40:03PM +0100, Jonas Oberhauser wrote:

> We first discuss why the more standard definition does not work well for
> language models like LKMM. For example, consider
> 
>     r1 = *a;
>     *b = 1;
>     if (*a == 1)

      if (r1 == 1) 

?

>       *b = 1;
>     *c = *b;
> 
> In the execution where r1 == 1, there is a control dependency from
> the load of *a to the second store to *b, from which the load to *b reads,
> and the store to *c has a data dependency on this load from *b. Nevertheless
> there is no semantic dependency from the load of *a to the store to *c; the
> compiler could easily replace the last line with *c = 1 and move this line to
> the top as follows:
> 
>     *c = 1;
>     r1 = *a;
>     *b = 1;
> 
> Since there is no order imposed by this sequence of syntactic dependencies
> and reads, syntactic dependencies can not by themselves form an acyclic
> relation.
> 
> In turn, there are some sequences of syntactic dependencies and reads that do
> form semantic dependencies, such as
> 
>     r1 = *a;
>     *b = 2;
>     if (*a == 1)

 r1 again?

>       *b = 1;
>     *c = *b;
> 
> Here we would consider that the store to *c has a semantic data dependency on
> the read from *a, given that depending on the result of that read, we store
> either the value 1 or 2 to *c.