Re: [PATCH v8 2/6] cgroup,cgroup/dmem: Add (dmem_)cgroup_common_ancestor helper
Thadeu Lima de Souza Cascardo <[email protected]> Tue, 4 Aug 2026 17:56:38 -0300
| Newsgroups | org.freedesktop.lists.dri-devel,org.kernel.vger.cgroups |
|---|---|
| Message-ID | <[email protected]> |
On Tue, Aug 04, 2026 at 10:41:25PM +0200, Maarten Lankhorst wrote: > Hey, > > On 8/4/26 22:26, Natalie Vock wrote: > > On 8/4/26 22:18, Maarten Lankhorst wrote: > >> > >> > >> On 8/4/26 10:25, Natalie Vock wrote: > >>> This helps to find a common subtree of two resources, which is important > >>> when determining whether it's helpful to evict one resource in favor of > >>> another. > >>> > >>> To facilitate this, add a common helper to find the ancestor of two > >>> cgroups using each cgroup's ancestor array. > >>> > >>> Signed-off-by: Natalie Vock <[email protected]> > >>> --- > >>>  include/linux/cgroup.h     | 21 +++++++++++++++++++++ > >>>  include/linux/cgroup_dmem.h | 9 +++++++++ > >>>  kernel/cgroup/dmem.c       | 41 +++++++++++++++++++++++++++++++++++++++++ > >>>  3 files changed, 71 insertions(+) > >>> > >>> diff --git a/include/linux/cgroup.h b/include/linux/cgroup.h > >>> index f2aa46a4f871e..83a17ded1c516 100644 > >>> --- a/include/linux/cgroup.h > >>> +++ b/include/linux/cgroup.h > >>> @@ -623,6 +623,27 @@ static inline struct cgroup *cgroup_ancestor(struct cgroup *cgrp, > >>>      return cgrp->ancestors[ancestor_level]; > >>>  } > >>>  +/** > >>> + * cgroup_common_ancestor - find common ancestor of two cgroups > >>> + * @a: first cgroup to find common ancestor of > >>> + * @b: second cgroup to find common ancestor of > >>> + * > >>> + * Find the first cgroup that is an ancestor of both @a and @b, if it exists > >>> + * and return a pointer to it. If such a cgroup doesn't exist, return NULL. > >>> + * > >>> + * This function is safe to call as long as both @a and @b are accessible. > >>> + */ > >>> +static inline struct cgroup *cgroup_common_ancestor(struct cgroup *a, > >>> +                           struct cgroup *b) > >>> +{ > >>> +   int level; > >>> + > >>> +   for (level = min(a->level, b->level); level >= 0; level--) > >>> +       if (a->ancestors[level] == b->ancestors[level]) > >>> +           return a->ancestors[level]; > >>> +   return NULL; > >>> +} > >>> + > >>>  /** > >>>   * task_under_cgroup_hierarchy - test task's membership of cgroup ancestry > >>>   * @task: the task to be tested > >>> diff --git a/include/linux/cgroup_dmem.h b/include/linux/cgroup_dmem.h > >>> index 1a88cd0c9eb00..9d72457c4cb9d 100644 > >>> --- a/include/linux/cgroup_dmem.h > >>> +++ b/include/linux/cgroup_dmem.h > >>> @@ -28,6 +28,8 @@ bool dmem_cgroup_below_min(struct dmem_cgroup_pool_state *root, > >>>                 struct dmem_cgroup_pool_state *test); > >>>  bool dmem_cgroup_below_low(struct dmem_cgroup_pool_state *root, > >>>                 struct dmem_cgroup_pool_state *test); > >>> +struct dmem_cgroup_pool_state *dmem_cgroup_get_common_ancestor(struct dmem_cgroup_pool_state *a, > >>> +                                  struct dmem_cgroup_pool_state *b); > >>>   void dmem_cgroup_pool_state_put(struct dmem_cgroup_pool_state *pool); > >>>  #else > >>> @@ -75,6 +77,13 @@ static inline bool dmem_cgroup_below_low(struct dmem_cgroup_pool_state *root, > >>>      return false; > >>>  } > >>>  +static inline > >>> +struct dmem_cgroup_pool_state *dmem_cgroup_get_common_ancestor(struct dmem_cgroup_pool_state *a, > >>> +                                  struct dmem_cgroup_pool_state *b) > >>> +{ > >>> +   return NULL; > >>> +} > >>> + > >>>  static inline void dmem_cgroup_pool_state_put(struct dmem_cgroup_pool_state *pool) > >>>  { } > >>>  diff --git a/kernel/cgroup/dmem.c b/kernel/cgroup/dmem.c > >>> index 9df3b33c65046..a587611ca2235 100644 > >>> --- a/kernel/cgroup/dmem.c > >>> +++ b/kernel/cgroup/dmem.c > >>> @@ -762,6 +762,47 @@ bool dmem_cgroup_below_low(struct dmem_cgroup_pool_state *root, > >>>  } > >>>  EXPORT_SYMBOL_GPL(dmem_cgroup_below_low); > >>>  +/** > >>> + * dmem_cgroup_get_common_ancestor(): Find the first common ancestor of two pools. > >>> + * @a: First pool to find the common ancestor of. > >>> + * @b: First pool to find the common ancestor of. > >>> + * > >>> + * Return: The first pool that is a parent of both @a and @b, or NULL if either @a or @b are NULL, > >>> + * or if such a pool does not exist. A reference to the returned pool is grabbed and must be > >>> + * released by the caller when it is done using the pool. > >>> + */ > >>> +struct dmem_cgroup_pool_state *dmem_cgroup_get_common_ancestor(struct dmem_cgroup_pool_state *a, > >>> +                                  struct dmem_cgroup_pool_state *b) > >>> +{ > >>> +   struct cgroup *ancestor_cgroup; > >>> +   struct cgroup_subsys_state *ancestor_css; > >>> +   struct dmemcg_state *ancestor_dmemcs = NULL; > >>> +   struct dmem_cgroup_pool_state *pool = NULL; > >>> + > >>> +   if (!a || !b) > >>> +       return NULL; > >>> + > >>> +   ancestor_cgroup = cgroup_common_ancestor(a->cs->css.cgroup, b->cs->css.cgroup); > >>> +   if (!ancestor_cgroup) > >>> +       return NULL; > >>> + > >>> +   rcu_read_lock(); > >>> +   ancestor_css = cgroup_e_css(ancestor_cgroup, &dmem_cgrp_subsys); > >>> +   if (css_tryget(ancestor_css)) > >>> +       ancestor_dmemcs = css_to_dmemcs(ancestor_css); > >>> +   rcu_read_unlock(); > >>> + > >>> +   if (ancestor_dmemcs) { > >>> +       pool = get_cg_pool_unlocked(css_to_dmemcs(ancestor_css), > >>> +                       a->region); > >>> +       if (IS_ERR(pool)) > >>> +           pool = NULL; > >> This should probably be a warn_on as this can never happen, sashiko is wrong here. > >> > >> If a and b are charged, all their ancestors are charged too. And when they share a > >> common ancestor, then the common ancestor has to have an existing charged pool as > >> well because there's a huge bug in the code otherwise. > >> > >>> +       css_put(ancestor_css); > >>> +   } > >>> +   return pool; > >>> +} > >>> +EXPORT_SYMBOL_GPL(dmem_cgroup_get_common_ancestor); > >>> + > >>>  static int dmem_cgroup_region_capacity_show(struct seq_file *sf, void *v) > >>>  { > >>>      struct dmem_cgroup_region *region; > >>> > >> > >> Otherwise looks good, so feel free to extend my r-b to this patch too, and with that minor fix up commit it. > > > > Thanks a lot! Correct me if I'm wrong here as it's been a while, but I think sashiko's current comment about the css_put(ancestor_css) being wrong seems to have merit too? Since dmem_cgroup_pool_state_put() also puts a css reference but get_cg_pool_unlocked does not get another reference to the css on its own? (Kind of a footgun if you ask me, but not something for this series) > > > > Mind if I also drop the css_put() line while I'm at it and *then* (finally :D) commit? > I'd keep the css_put for the failure case then. > > Since the get_cg_pool_unlocked() is a local function, it's less of an issue that it doesn't > obtain a reference itself, as all callers outside dmemcg.c never notice. > > Maybe do a final round of testing too, in case it introduces new failures. :-) > > Especially device unload/reload might show double puts. But otherwise looks good to me. > > Kind regards, > ~Maarten I wrote the fixup at [1] that included that css_put. I will look into the possibility of get_cg_pool_unlocked returning NULL or error. But I find that unconditionally calling css_put here is wrong. If pool is NULL, it needs to be called, because otherwise the css_tryget will be unbalanced. The reason not to call it unconditionally is that it will be called when dmem_cgroup_pool_state_put is caled, hence, balancing the css_tryget. I also need to consider whether doing it outside the RCU section is fine. I just looked here and one of the possibilities for pool to be NULL is that the region is unregistered in a race condition. region->unregistered is protected by dmemcg_lock, but that is taken by get_cg_pool_unlocked, so it seems possible. By the way, while testing the whole series, I see many different issues here that I am still looking at as they may be otherwise hidden pre-existing bugs. Regards. Cascardo. [1] https://lore.kernel.org/cgroups/[email protected]/