Re: [PATCH bpf-next v5 02/11] bpf: Add helpers to describe the R0:R2 return register pair

Eduard Zingerman <[email protected]>
Newsgroups org.kernel.vger.bpf
Message-ID <[email protected]>
On Thu, 2026-08-13 at 13:02 -0700, Yonghong Song wrote:

...

> +static void bpf_compute_subprog_ret_regs(struct bpf_verifier_env *env)
> +{
> +	const struct btf *btf = env->prog->aux->btf;
> +	const struct btf_type *type;
> +	int subprog;
> +	u32 size;
>  
> -	return btf_type_is_void(type);
> +	for (subprog = 0; subprog < env->subprog_cnt; subprog++) {
> +		type = subprog_ret_type(env, subprog);
> +		if (!type || !(btf_type_is_struct(type) || btf_type_is_scalar(type)))
> +			continue;

Is the check '!(btf_type_is_struct(type) || btf_type_is_scalar(type))'
needed after v4->v5 migration?

> +		if (IS_ERR(btf_resolve_size(btf, type, &size)))
> +			continue;

Let's propagate this error instead of ignoring it. Or add WARN_ON_ONCE().
After BTF validation it shouldn't really happen.

> +		if (ret_regs_cnt(size) > 1) {
> +			subprog_info(env, subprog)->ret_reg_pair = true;
> +			/*
> +			 * The R0:R2 return convention is only implemented in
> +			 * the JIT: the interpreter propagates BPF_R0 alone out
> +			 * of a subprogram, so a caller reading R2 would see a
> +			 * stale value.
> +			 */
> +			env->prog->jit_required = 1;
> +		}
> +	}
>  }
>  
>  static const char *subprog_name(const struct bpf_verifier_env *env, int subprog)

...

Regarding the bot comment:

> Additionally, should jit_required be set for subprogs whose BTF prototypes
> are marked unreliable?  btf_check_subprog_call() can flag a mismatch with
> prog->aux->func_info_aux[subprog].unreliable = true, and check_func_call()
> only aborts on -EFAULT, so a static callee with an aggregate return can
> load today without using the BTF return type. Subprogs subsequently deleted
> by bpf_opt_remove_dead_code() (which runs after this pass) also don't need
> jit_required set.

It seem to be correct. As prepare_func_exit() unconditionally copies
r0 and r2 to caller's frame, the verifier would conclude that r2 is
initialized; while interpreter won't copy it. One option is to force
nregs == 1 if there is no jit.

(Or derive this information not from BTF, I'll comment on that later).
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