Re: getting at raw command line

As i said, when you start program 'p whatever ' %esp
points place on stack where number of parameters was
put ex. 
$p 1 2 3 -> movl (%esp),%ecx => %ecx=3 )

next (%esp+4) adress of program name ex. 

$/home/usr/bin/p 1 2 3 -> (%esp+4) adres of string
"/home/usr/bin/p"

(%esp+8)(+16 if you have 64-bit arch) adress of text
string of first parameter, so if you write

$ p * -> movl (%esp+8),%ecx / movq (%rsp+16),%rcx
        movl (%ecx),%ebx / movq (%rcx),%rbx
       %ecx=42 ( '*' )
so now you can do with it whatever you want ( write
using SYS_WRITE, printf etc )
Lukas


--- Jack Andrews <[email protected]> wrote:

> the shell changes arguments like * to a number of
> arguments.  is there
> a way to get the *?  that is, if my program is p, i
> want this
> behaviour:
> 
>  $ ls
>  file.1 file.2
>  $ ls *
>  file.1 file.2
>  $ p file.1
>  file.1
>  $ p *
>  *
> 
> i don't want
> 
>  $ p *
>  file.1 file.2
> -
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