Re: [PATCH] btrfs: compression: allocate buckets with workspace
Sun YangKai <[email protected]>
| Newsgroups | org.kernel.vger.linux-btrfs,org.kernel.vger.linux-kernel |
|---|---|
| Message-ID | <[email protected]> |
On 2026/6/29 08:25, Rosen Penev wrote: > Convert 3 allocations into one. Simplifies code slightly. > > Signed-off-by: Rosen Penev <[email protected]> > --- > fs/btrfs/compression.c | 18 +++++------------- > 1 file changed, 5 insertions(+), 13 deletions(-) > > diff --git a/fs/btrfs/compression.c b/fs/btrfs/compression.c > index ffb6b52863a7..da6749ff5924 100644 > --- a/fs/btrfs/compression.c > +++ b/fs/btrfs/compression.c > @@ -650,11 +650,11 @@ struct heuristic_ws { > /* Partial copy of input data */ > u8 *sample; > u32 sample_size; > - /* Buckets store counters for each byte value */ > - struct bucket_item *bucket; > /* Sorting buffer */ > struct bucket_item *bucket_b; > struct list_head list; > + /* Buckets store counters for each byte value */ > + struct bucket_item bucket[]; > }; > > static void free_heuristic_ws(struct list_head *ws) > @@ -664,8 +664,6 @@ static void free_heuristic_ws(struct list_head *ws) > workspace = list_entry(ws, struct heuristic_ws, list); > > kvfree(workspace->sample); > - kfree(workspace->bucket); > - kfree(workspace->bucket_b); > kfree(workspace); > } > > @@ -673,22 +671,16 @@ static struct list_head *alloc_heuristic_ws(struct btrfs_fs_info *fs_info) > { > struct heuristic_ws *ws; > > - ws = kzalloc_obj(*ws); > + ws = kzalloc(struct_size(ws, bucket, BUCKET_SIZE * 2), GFP_KERNEL); It seems that size is fixed and known at compile time, and since we want to inline the buckets in the struct, I think we can have something like this to save one pointer: struct heuristic_ws { ... struct bucket_item bucket[BUCKET_SIZE]; struct bucket_item bucket_b[BUCKET_SIZE]; } However, each bucket array takes exactly 1024B memory. Currently we have a 48B allocation for the struct it self, 2 * 1024B allocation for bucket array, and 8192B allocation for sample. With these 2 arrays inlined, the struct will need 32 + 2048B allocation if my calculation is correct, which will goes into kmalloc-4k. Seems not good. Thanks, Sun YangKai > if (!ws) > return ERR_PTR(-ENOMEM); > > + ws->bucket_b = ws->bucket + BUCKET_SIZE; > + > ws->sample = kvmalloc(MAX_SAMPLE_SIZE, GFP_KERNEL); > if (!ws->sample) > goto fail; > > - ws->bucket = kzalloc_objs(*ws->bucket, BUCKET_SIZE); > - if (!ws->bucket) > - goto fail; > - > - ws->bucket_b = kzalloc_objs(*ws->bucket_b, BUCKET_SIZE); > - if (!ws->bucket_b) > - goto fail; > - > INIT_LIST_HEAD(&ws->list); > return &ws->list; > fail: