Byte ordering

Hi all,

Given some codes:

...
unsigned int val = 0x0a0b0c0d;
unsigned char *str;

str = (unsigned char *) &val;
printf("%.2x %.2x %.2x %.2x\n", *str, *(str + 1), *(str + 2), *(str + 3));
...

the output is  " 0d 0c 0b 0a "

the given codes try to divide a 32 bit integer into it's 8 bit nibbles.
with bit shifting and masking ( that you all teach me.... thanks u ;)
) i can get it correctly:

printf("%.2x %.2x %.2x %.2x\n", val >> 24 & 0xff, val >> 16 & 0xff,
val >> 8 & 0xff, val & 0xff));  /* 0a 0b 0c 0d */

but when address it with pointer to character i got it reversed, could
you please explain me why pointer to character reverse the ordering?
if what i need is only to reverse the ordering (pointer to character
index) to get a valid order? and if this a valid method?

              - Randi