Re: C program help

On Sat, Sep 19, 2009 at 8:43 PM, spiros85 <[email protected]> wrote:
>
> Hi guys of dear forum!I am a new programmer in C programming language and i
> have a question for you about the following C code:
> #include <stdio.h>
> #include <stdlib.h>
>
> int main()
> {
>    int x;
>    int answer;
>    int right;
>    int wrong;
>    printf("This is a program of sum\n");
>    right = 0; /*Initialization of right value*/
>    wrong = 0; /*Initialization of wrong value*/
>    for(x = 1; x <= 10; x++)[QUOTE][/QUOTE]
>    {
>          printf("What is %d + %d: ", x, x);
>          scanf("%d", &answer);
>          printf("The sum is %d\n", answer);
>          printf("\a");
>          if(answer == x + x)
>          {
>             printf("%d is RIGHT answer\n", answer);
>             right++; /*Saves and increases the amount of right answers*/
>          }
>          else
>          {
>             printf("%d is WRONG answer\n", answer);
>             b[10] = answer;
>             wrong++; /*Saves and increases the amount of wrong answers*/
>             printf("The correct answer is %d\n", x + x);
>          }
>    }
>    printf("The right answers are %d and the wrong are %d\n", right, wrong);
>    fflush(stdin);
>    getchar();
> }
>
> First, I use DEV C++ compiler!This program asks from user to find the sum of
> 1+1,2+2 until for loop reaches 10.As you can observe with right++ and
> wrong++ i can define and print to the screen the amount of right or wrong
> numbers!
> My question is how could I define the number of correct and wrong numbers in
> collaboration with their amount?For example:
> The right answers are 8 and wrong are 2
> The right answers are 2 4 6 8 10 12 14 16
> The wrong answers are 22 44

#include<stdio.h>
#define N 10
int main() {
	int answer;
	int i;
	int result[N][2];
	int right = 0, wrong = 0;

	for (i=1;i<=N;i++) {
		printf("What is %i + %i ? :",i,i);
		scanf("%d",&answer);
		if (i+i == answer) {
			result[i-1][0] = answer;
			result[i-1][1] = 1;
			right++;
		} else {
			result[i-1][0] = answer;
			result[i-1][1] = 0;
			wrong++;
		}
	}

	printf ("The right answers are %d and wrong answers are %d\n",right, wrong);
	printf("The right answers are : ");
	for (i=0;i<N;i++) {
		if (result[i][1]) {
			printf("%d ", result[i][0]);
		}
	}
	printf("\n");
	printf("The wrong answers are : ");
	for (i=0;i<N;i++) {
		if (!result[i][1]) {
			printf("%d ", result[i][0]);
		}
	}
	printf("\n");
	return 0;
}



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-- 
Thanks -
Manish
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