Re: C program help

here is solution
 
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int x;
    int answer;
    int right;
    int wrong;
    int righta[100];
    int wronga[100];
    int i;

    printf("This is a program of sum\n");
    right = 0; /*Initialization of right value*/
    wrong = 0; /*Initialization of wrong value*/
    for(x = 1; x <= 10; x++)
    {
          printf("What is %d + %d: ", x, x);
          scanf("%d", &answer);
          printf("The sum is %d\n", answer);
          printf("\a");
          if(answer == x + x)
          {
             printf("%d is RIGHT answer\n", answer);
             righta[right]=answer;
             right++; /*Saves and increases the amount of right answers*/
          }
          else
          {
             printf("%d is WRONG answer\n", answer);
             wronga[wrong] = answer;
             wrong++; /*Saves and increases th      }
    }
    righta[right]=0;
    wronga[wrong]=0;
    printf("The right answers are %d and the wrong are %d\n", right, wrong);
    printf("The right answers are ");
    for(i=0;righta[i];i++){
        printf("%d\t",righta[i]);
    }
    printf("\nThe wrong answers are ");
    for(i=0;wronga[i];i++){
        printf("%d\t",wronga[i]);
    }
    fflush(stdin);
    getchar();
}



e amount of wrong answers*/
             printf("The correct answer is %d\n", x + x);
                                                                                              





spiros85 wrote:
> 
> Hi guys of dear forum!I am a new programmer in C programming language and
> i have a question for you about the following C code:
> #include <stdio.h>
> #include <stdlib.h>
> 
> int main()
> {
>     int x;
>     int answer;
>     int right;
>     int wrong;
>     printf("This is a program of sum\n");
>     right = 0; /*Initialization of right value*/
>     wrong = 0; /*Initialization of wrong value*/
>     for(x = 1; x <= 10; x++)[QUOTE][/QUOTE]
>     {
>           printf("What is %d + %d: ", x, x);
>           scanf("%d", &answer);
>           printf("The sum is %d\n", answer);
>           printf("\a");
>           if(answer == x + x)
>           {
>              printf("%d is RIGHT answer\n", answer);
>              right++; /*Saves and increases the amount of right answers*/
>           }
>           else
>           {
>              printf("%d is WRONG answer\n", answer);
>              b[10] = answer;
>              wrong++; /*Saves and increases the amount of wrong answers*/
>              printf("The correct answer is %d\n", x + x);
>           }
>     }
>     printf("The right answers are %d and the wrong are %d\n", right,
> wrong);
>     fflush(stdin);
>     getchar();
> }
>  
> First, I use DEV C++ compiler!This program asks from user to find the sum
> of 1+1,2+2 until for loop reaches 10.As you can observe with right++ and
> wrong++ i can define and print to the screen the amount of right or wrong
> numbers!
> My question is how could I define the number of correct and wrong numbers
> in collaboration with their amount?For example:
> The right answers are 8 and wrong are 2
> The right answers are 2 4 6 8 10 12 14 16
> The wrong answers are 22 44
> 

-- 
View this message in context: http://www.nabble.com/C-program-help-tp25522429p25820023.html
Sent from the linux-c-programming mailing list archive at Nabble.com.