Re: Re: Re: Function pointers

simon wrote:

> char (*pa())[4]; 
> is this mean that an pa function pointer with return value like a char a[4] and it's argument is nothing ?
> 
> right?

Wrong.

1. pa is not a pointer to a function, it's a function which returns a
pointer. "()" has higher precedence than "*", so "*pa()" is parsed as
"*(pa())" (function returning pointer) rather than "(*pa)()" (pointer
to function).

2. An empty parameter list "()" indicates that the function takes
unspecified arguments. A function which takes no arguments has
"(void)" as the parameter list.

-- 
Glynn Clements <[email protected]>