printf *%f
ratheesh k <[email protected]> Wed, 12 Jan 2011 13:09:08 +0530
| Newsgroups | org.kernel.vger.linux-c-programming |
|---|---|
| Message-ID | <[email protected]> |
double x=45.9876 ;
printf("%4.2f" , x); is working fine ... But printf("%*f , 4.2 , x) ;
behaves odd in my fedora 8 pentium machine. any clue ?
Does * substitute only integers ?
-Ratheesh