Re: duplicated modulo
Nicolas Kaiser <[email protected]> Fri, 1 Apr 2011 12:19:16 +0200
| Newsgroups | org.kernel.vger.linux-c-programming |
|---|---|
| Message-ID | <[email protected]> |
* "Michal Nazarewicz" <[email protected]>: > On Fri, 01 Apr 2011 11:41:13 +0200, Nicolas Kaiser wrote: > > I'm curious: a duplicated modulo operation can't possibly make > > any difference, can it? > > > > diff -u -p ./arch/powerpc/platforms/powermac/nvram.c > > /tmp/nothing/arch/powerpc/platforms/powermac/nvram.c > > --- ./arch/powerpc/platforms/powermac/nvram.c 2011-03-31 > > 09:52:41.674292401 +0200 > > +++ /tmp/nothing/arch/powerpc/platforms/powermac/nvram.c > > @@ -246,7 +246,6 @@ static u32 core99_calc_adler(u8 *buffer) > > high = 0; > > for (cnt=0; cnt<(NVRAM_SIZE-CORE99_ADLER_START); cnt++) { > > if ((cnt % 5000) == 0) { > > - high %= 65521UL; > > high %= 65521UL; > > } > > low += buffer[cnt]; > > It's not just a module. It's also an assignment. Sure. But I fail to see where between a %= b; a %= b; and a = (a % b) % b; and a %= b; would be a difference? Best regards, Nicolas Kaiser