Pointer to a char

Hi, having coding in C for 3 years but I'm still not clear with this one.
Consider this code.

...
char *p;
unsigned int i = 0xcccccccc;
unsigned int j;

p = (char *)  &i;
printf("%.2x %.2x %.2x %.2x\n", *p, p[1], p[2], p[3]);

memcpy(&j, p, sizeof(unsigned int));
printf("%x\n", j);
...

Output:

ffffffcc ffffffcc ffffffcc ffffffcc
0xcccccccc


My questions are:

1. Why it prints "ffffffcc ffffffcc ffffffcc ffffffcc"? (if p is
unsigned char* then it will print correctly "cc cc cc cc")
2. Why pointer to char p copied to j correctly, why not every member
in p overflow? since it is a signed char.

Regards.