Re: How calls diald the pppd?
Juergen Kosel <[email protected]> Thu, 29 Aug 2002 22:48:51 +0200
| Newsgroups | org.kernel.vger.linux-diald |
|---|---|
| Message-ID | <[email protected]> |
Rod wrote: > > > mode ppp > > pppd-options usepeerdns name juergen.kosel noipdefault ipcp-accept-local ipcp-accept-remote > > path-pppd /usr/sbin/pppd > > device /dev/ttyS0 > > connect /etc/ppp/dial-freenet > > #connect /usr/local/lib/diald/connect > > speed 115200 > > modem > > lock > > crtscts > > local 192.168.2.1 > > #remote 62.104.216.42 > > Pick a local and remote address that are unique and not the address of > any machines in your network. As an example if the diald server in my > network has an IP address of 192.168.2.1 my diald.conf has the following > > local 192.168.2.2 > remote 192.168.2.3 My machine is standalone (unless conecting to ISP) So the IP adresses are uniqe! And in pap secrets the remote and local adress field has an '*' as entry (match any) for the choosen name. So I have no idea why the ppp options ipcp-accept-local ipcp-accept-remote have no effect. And I allready tried 0.0.0.0:0.0.0.0 in the ppp options. Juergen