what is purpose of "$(O)" in top-level docs Makefile?
"Robert P. J. Day" <[email protected]>
| Newsgroups | org.yoctoproject.lists.docs |
|---|---|
| Message-ID | <[email protected]> |
almost certainly a dumb question but was perusing the top-level docs
Makefile and read at the bottom:
# Catch-all target: route all unknown targets to Sphinx using the new
# "make mode" option. $(O) is meant as a shortcut for $(SPHINXOPTS).
%:
$(SOURCEDIR)/set_versions.py
@$(SPHINXBUILD) -M $@ "$(SOURCEDIR)" "$(BUILDDIR)" $(SPHINXOPTS) $(O)
it's unclear to me what the point of $(O) is if it's supposed to be
a "shortcut" for $(SPHINXOPTS) when they're both incorporated in that
build command. can someone clarify what is going on here?
rday