cvs commit: perlfaq perlfaq4.pod

cvsuser     02/07/17 10:46:17

  Modified:    .        perlfaq4.pod
  Log:
  * How do I expand function calls in a string?
  
  removed the example that tries to use scalar context in ().
  it just doesn't work
  
  Revision  Changes    Path
  1.26      +6 -9      perlfaq/perlfaq4.pod
  
  Index: perlfaq4.pod
  ===================================================================
  RCS file: /cvs/public/perlfaq/perlfaq4.pod,v
  retrieving revision 1.25
  retrieving revision 1.26
  diff -u -w -r1.25 -r1.26
  --- perlfaq4.pod	30 May 2002 07:04:25 -0000	1.25
  +++ perlfaq4.pod	17 Jul 2002 17:46:17 -0000	1.26
  @@ -1,6 +1,6 @@
   =head1 NAME
   
  -perlfaq4 - Data Manipulation ($Revision: 1.25 $, $Date: 2002/05/30 07:04:25 $)
  +perlfaq4 - Data Manipulation ($Revision: 1.26 $, $Date: 2002/07/17 17:46:17 $)
   
   =head1 DESCRIPTION
   
  @@ -557,14 +557,6 @@
   
       print "My sub returned @{[mysub(1,2,3)]} that time.\n";
   
  -If you prefer scalar context, similar chicanery is also useful for
  -arbitrary expressions:
  -
  -    print "That yields ${\($n + 5)} widgets\n";
  -
  -Version 5.004 of Perl had a bug that gave list context to the
  -expression in C<${...}>, but this is fixed in version 5.005.
  -
   See also ``How can I expand variables in text strings?'' in this
   section of the FAQ.
   
  @@ -1398,6 +1390,11 @@
   	$_ **= 3;
   	$_ *= (4/3) * 3.14159;  # this will be constant folded
       }
  +    
  +which can also be done with map() which is made to transform
  +one list into another:
  +
  +	@volumes = map {$_ ** 3 * (4/3) * 3.14159} @radii;
   
   If you want to do the same thing to modify the values of the
   hash, you can use the C<values> function.  As of Perl 5.6