cvs commit: perlfaq perlfaq4.pod

[email protected] (brian d foy)
Newsgroups perl.cvs.perlfaq
Message-ID <[email protected]>
cvsuser     03/01/31 09:36:16

  Modified:    .        perlfaq4.pod
  Log:
  * re-jiggered the question to get rid of the hyphens
  
  * expanded the answer using POSIX, Time::Local, and Date::Calc
  
  Revision  Changes    Path
  1.41      +27 -6     perlfaq/perlfaq4.pod
  
  Index: perlfaq4.pod
  ===================================================================
  RCS file: /cvs/public/perlfaq/perlfaq4.pod,v
  retrieving revision 1.40
  retrieving revision 1.41
  diff -u -w -r1.40 -r1.41
  --- perlfaq4.pod	26 Jan 2003 17:43:21 -0000	1.40
  +++ perlfaq4.pod	31 Jan 2003 17:36:16 -0000	1.41
  @@ -1,6 +1,6 @@
   =head1 NAME
   
  -perlfaq4 - Data Manipulation ($Revision: 1.40 $, $Date: 2003/01/26 17:43:21 $)
  +perlfaq4 - Data Manipulation ($Revision: 1.41 $, $Date: 2003/01/31 17:36:16 $)
   
   =head1 DESCRIPTION
   
  @@ -353,12 +353,33 @@
   
   =head1 Data: Dates
   
  -=head2 How do I find the week-of-the-year/day-of-the-year?
  +=head2 How do I find the day or week of the year?
   
  -The day of the year is in the array returned by localtime() (see
  -L<perlfunc/"localtime">):
  +The localtime function returns the day of the week.  Without an
  +argument localtime uses the current time.
   
  -    $day_of_year = (localtime(time()))[7];
  +    $day_of_year = (localtime)[7];
  +    
  +The POSIX module can also format a date as the day of the year or
  +week of the year.
  +
  +	use POSIX qw/strftime/;
  +	my $day_of_year  = strftime "%j", localtime;
  +	my $week_of_year = strftime "%W", localtime;
  +
  +To get the day of year for any date, use the Time::Local module to get
  +a time in epoch seconds for the argument to localtime.
  +	
  +	use POSIX qw/strftime/;
  +	use Time::Local;
  +	my $week_of_year = strftime "%W", 
  +		localtime( timelocal( 0, 0, 0, 18, 11, 1987 ) );
  +
  +The Date::Calc module provides two functions for to calculate these.
  +
  +	use Date::Calc;
  +	my $day_of_year  = Day_of_Year(  1987, 12, 18 );
  +	my $week_of_year = Week_of_Year( 1987, 12, 18 );
   
   =head2 How do I find the current century or millennium?
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