Re: I'd tell you how long it'll take for my hair to fall out but I'm struggling with duration!

Kristian Flint wrote:
>definitely a fixed number of seconds in a day

Leap seconds.  DateTime doesn't really do them correctly -- actually its
time scale is a bit schizophrenic at the sub-second level -- but it does
represent leap seconds that it knows about.  So some days, about one in
500, have 86401 seconds.

>                                              (actually unless we're
>talking about that tiny fraction that ends up counting towards a quarter
>of a day per year?).

No.  That's a leap day occuring roughly every four years, which means
that there isn't a fixed number of days per year.

>This doesn't actually return what's stated above (#) but actually
>returns
>0 years, 41 months, 1 days, 00 hours, 375 minutes, 45 seconds

Hmm, yes.  DateTime::Duration is normalising to that form.
DT::F::Duration is only showing what it gets from DT::Duration.
Looks like DT::F::Duration is trying to normalise the other way, back
to what you input, but that's going wrong somewhere.

>And if I try and make the pattern => '%e' to just get the number of
>days, this returns 0!

Returns 1 for me.

-zefram