Re: Some random reflections on tpr05a

En op 09 september 2002 sprak Tina Mueller:
> On Mon, 9 Sep 2002, Eugene van der Pijll wrote:
>
> > a1z + a2z * a3z + a4z * (a5z + a6z) + a7z
> 
> you wouldn't need two markers. a\d+ would be enough cause
> after a number there will always follow a non-digit.

No, a\d+ wouldn't be enough. After the expansion of the ()'s, part of
this expression would be

a4z * a5 6 +z + a7z

To match the second factor, we need the 'z'. a\d+ is not enough; that
would only match a5. The regexp /(a.*?)[+-]a/ does find the correct term.

And this is approximately what I did. Except that I didn't remove the
z's; I removed the a's. So you do indeed need only one marker.

> that's what our solution made:
> put every innermost expression in the stack, (that means expressions
> in parentheses or surrounded by '+' or '-') and replace it with
> 'a'.index of stack element.
<snip>
> 
> i hope the description of our only 165 strokes-solution wasn't too boring...

165? Ha! I had a similar solution, but mine was only 131 strokes!

In the post mortem, it's in the category 'Rejected'...

(-ugene

-- 
When I'm playing golf, I always expect to knock the ball into the hole.
And I'm happy if the ball ends up closer to the hole than it was.
 -- |_arry \\/all