Re: Question about activestate perl

I think shift applies to an array, not to an argument.

Try

#!/usr/local/ActivePerl-5.8/bin/perl -w

my $test = $ARGV[0] ;
print "$test\n";

to read the first argument (hello) from the array ARGV


Sincerely,

Arno H.P. Reuser
CEO, Reuser's Information Services
KvK 2731 2325
----
http://www.reuser.biz
[email protected]



Anne L. Highsmith wrote:
> (Sorry if this is a duplicate. But I didn't see my first message distributed, so I'm re-sending from another address)
> 
> This is REALLY embarrassing. 
> 
> After a loooooooooong  hiatus, I need to go back to using activestate perl on my pc to do some work.  I don't know whether it's me or my PC or the phase of the moon, but I can't get my program to recognize command line arguments.  I backed off to the simplest program, i.e.
> ---------------------------------------------------------------
> #!/usr/local/ActivePerl-5.8/bin/perl -w
> 
> my $test = shift;
> print "$test\n";
> ----------------------------------------------------------------
> 
> and I invoke it from the dos window command line as:
> 
> C:\Perl\apps\urls>test.pl Hello
> 
> and I get:
> 
> Use of uninitialized value in concatenation (.) or string at C:\Perl\apps\urls\test.pl line 4.
> 
> What the HECK am I doing wrong? I've tried enclosing the command line arguments in single quotes, double quotes and rubber galoshes, but I get the same response.
> I tried changing "my $test = shift;" to "my $test = $ARGV[0];".  I copied the program back to my unix box, with just a change of the shebang line, and it works fine.
> 
> When I hardcode the 'Hello' it works fine.
> 
> I figure this has to be excruciatingly simple, but I can't see it. Help?
> 
>