Re: Turning MARC record object back into a string

If I'm not wrong, sprintf syntax is
sprintf FORMAT, LIST
See http://perldoc.perl.org/functions/sprintf.html for instance.
So the statement
my $new_marc = $bib_rec->as_usmarc();
seems the good way to accomplish your need.
Bye. Stefano

On Mar 12, 2012, at 14:49 , Anne Highsmith wrote:

> I am running a perl program that uses an API to update MARC records in an ILS. Voyager & BatchCat, for you Voyager folks. I have to pass a bunch of parameters to the API, of course, including the updated marc record as a string. The input record is UTF8, so the output must be also. Previously, I've used this statement to turn the MARC record object back into a string:
> 
> my $new_marc = sprintf($bib_rec->as_usmarc());
> 
> I'm running into lots of problems with the latest batch of records I'm editing, however, because the data has lots of embedded percent signs (%), which perl is not interpreting as part of the data but as part of a perl command; it fails with some kind of error in sprintf.
> 
> I tried using this statement instead of the above: my $new_marc = $bib_rec->as_usmarc();
> 
> i.e. leaving sprintf out of it entirely. It seems to work WITHOUT the errors induced by the percent signs. 
> 
> Can anybody think of any reason why I shouldn't just use " my $new_marc = $bib_rec->as_usmarc();". And if you can, can you suggest an alternative way to correctly turn the object into a string?
> 
> 
>