Re: my \&foo = sub { }?
[email protected] (Aristotle Pagaltzis via perl5-porters) Sat, 18 Apr 2026 04:53:37 +0200
| Newsgroups | perl.perl5.porters |
|---|---|
| Message-ID | <[email protected]> |
* Eric Brine <[email protected]> [2026-04-08 01:41]: > When using the lexical_subs, refaliasing and declared_refs features, > > We have C<< my sub foo; \&foo = REF; >> > We have C<< my \$foo = REF; >> > Why don't we have C<< my \&foo = REF; >> Because we don’t have C<< my &foo >>.