Re: Literals, take 2

On Wed, Nov 13, 2002 at 07:26:06PM +0100, Angel Faus wrote:
> For example, the integer 30 can be written in hexadecimal base in two 
> equivalent ways:
> 
>   my $x = 16:1D
>   my $x = 16:1.14
> 
> These two representations are incompatible, so writing something like 
> C<16:D.13> will generate a compile-time error.

So, can we specify floats in other bases?  if we can why is 16:D.14 an
error?  Why isn't it a floating point number?  I think we can and we
need to demonstrate this with a three digit hex number.  We also need to
point out that there is a problem with the two digit example.

andrew
-- 
Taurus: (April. 20 - May 20)
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