[Fwd: Re: Numeric Literals (Summary)]

>>     0x00ff     # hex value ff
>>    '0x00ff'    # integer value 0, with trailing 'x00ff'
>>
>>I think ways to solve this should be open to discussion.  Hopefully 
>>Luke can give us some proposals, since he's writing that part.
>>    
>>
>
>The behavior described there should stay.  If you want literal-like
>interpretations of strings, use the C<oct> function.  The name of that
>function should probably be changed to something more appropriate.
>
>C<lit>, C<literal>, C<num> (ambiguous?), C<base>, etc.?
>
>Luke
>  
>
How about

my $a = 256:192.169.34.76;
my $b = $a.base(10);
my $c = '34:13.23.0.1.23.45'.base(16);

Or :

my $a = 256:192.169.34.76;
my $b = 10:$a;
my $c = 16:'34:13.23.0.1.23.45';

How would that work with
print "10:$a";
Would that have to be printf(...%r...) as mentioned elsewhere ?

R.

-- 
Richard Nuttall
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