Re: RFC 23 (v6) Higher order functions
[email protected] (John Tobey) Mon, 25 Sep 2000 20:27:07 -0400 (EDT)
| Newsgroups | perl.perl6.language.subs |
|---|---|
| Message-ID | <[email protected]> |
> That is, the expression:
>
> $check = ^_ == ^_**2 *^_ or die ^_;
Shouldn't that be
$check = (^_ == ^_**2 *^_ or die ^_);
due to precedence of = over "or"?
> is equivalent to:
>
> $check = sub (;$$$$) {
> $_[0] == $_[1]**2 *$_[2] or die $_[3]
> };
--
John Tobey, late nite hacker <[email protected]>
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