Re: Tying sub arguments is rare?

According to M.J.T. Guy:
> This has also concerned me.   You seem to be making tie operate on
> a reference to a reference, rather than just a reference.

Yes.  Or, more precisely, on an lvalue reference, a la
   \$a = \$b;
which we needed to make work anyway.

> Does this mean that code like this will break?
>      my @a = (1..5);
>      my $b = \($a[2]);
>      tie $a[2], 'MyWatcher';
>      $$b = 4;         # should be seen by watcher

Yes.

Doggone it, if I have to change this I'm going to be ticked.
-- 
Chip Salzenberg             - a.k.a. -              <[email protected]>
           "I am the Lemon Zester of Destruction!"  //MST3K