Re: .contains question

my $x="abc45def";
my @y=<a b c d e f g h i j 1 2 3 4 5>; say so $x.contains(any @y);

"so" will collapse the junction into a Bool.
"say" will append a \n for you, so you don't have to.

> On 11 Dec 2023, at 01:52, ToddAndMargo via perl6-users <[email protected]> wrote:
> 
>>> On 10 Dec 2023, at 21:36, ToddAndMargo via perl6-users <[email protected]> wrote:
>>> 
>>> Hi All,
>>> 
>>> my Str $x="abc3defg"; if $x.contains( "a" || "b" || "3" )  { print "True\n"; } else { print "False\n" };
>>> True
>>> 
>>> Is there a way to tell .contains that you want to know
>>> if any of a sequence characters is in a string other that
>>> repeating || over and over.  Any [a..z] or [0..9] option?
>>> 
>>> Many thanks,
>>> -T
> 
> On 12/10/23 15:24, Elizabeth Mattijsen wrote:
> > my @letters = <a b 3>;
> > if $x.contains(any @letters) {
> 
> 
> Hi Elizabeth,
> 
> Very interesting.  Problem: I was looking for one answer, not many
> 
> > my $x="abc45def";my @y=<a b c d e f g h i j 1 2 3 4 5>; print $x.contains(any @y) ~ "\n";
> True
> True
> True
> True
> True
> True
> False
> False
> False
> False
> False
> False
> False
> True
> True
> 
> 
> Many thanks,
> -T
> 
> -- 
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> They malfunction when you open windows
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>