Re: raku-toml confusion

On 5/24/25 2:40 AM, Peter Pentchev wrote:
> On Fri, May 23, 2025 at 05:44:01PM -0700, ToddAndMargo via perl6-users wrote:
>> Hi All,
>>
>> https://github.com/tony-o/raku-toml
>>
>> In the usage parsing example:
>>
>>      Parsing TOML
>>      use TOML;
>>      my $config = from-toml("config.toml".IO.slurp);
>>      # use $config like any ol' hash
>>
>> This makes perfect sense to me.
> 
> ...then you realize that the from-toml() function accepts a string,
> not a file, right? The string that was read from the "config.toml"
> file by the .IO.slurp() method.
> 
>> But in the Generating TOML example:
>>
>>     use TOML;
>>     my $config = {
>>       bands => ['green day',
>>                 'motorhead',
>>                 't swift',],
>>       favorite => 'little big',
>>     };
>>     my $toml-config = to-toml($config);
>>
>> I am confused.  Seems to me he left something out.
>> If this creates a TOML file for you, what/where
>> is the file name and path?  What am I missing?
> 
> ...and to-toml() also produces a string. If you want to write it to
> a file, you need to do that yourself later.
> 
> Hope that helps!
> 
> G'luck,
> Peter
> 


Hi Peter,

    Now I understand.  Spurt the string.  Thank you!

-T