Re: Update in perlop

Hi Prateek,

On Wed, 4 Sep 2013 12:19:17 +0000
"Balasundaram, Prateek" <[email protected]> wrote:

> Hello all,
> 
> In the section:
> http://perldoc.perl.org/perlop.html#Auto-increment-and-Auto-decrement
> 
> I believe this line is incorrect:
> "undef is always treated as numeric, and in particular is changed to 0 before
> incrementing (so that a post-increment of an undef value will return 0 rather
> than undef)."
> 
> Upon testing:
> $ perl -le '$val=undef;print("Initial Value: $val");$val++;print("Incremented
> Value: $val");' 
> Initial Value:
> Incremented Value: 1
> 

What is meant by that is that if you do:

shlomif@telaviv1:~$ perl -le 'use Data::Dumper; $x=undef; my $y = ($x++);print
Dumper([$y])'
$VAR1 = [
          0
        ];

shlomif@telaviv1:~$ 

Hope it helps.

Regards,

	Shlomi Fish

> It seems that the post-increment value of undef will be 1, not 0 as the
> documentation states.
> 
> Regards,
> Prateek
> --
> Prateek Balasundaram
> [email protected]
> (484)562-1281
> 

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