Re: Retrieve url path (host name plus path)
Florent André <[email protected]>
| Newsgroups | gmane.comp.cms.lenya.user |
|---|---|
| Message-ID | <[email protected]> |
On Thu, 15 Apr 2010 14:45:32 +0100, Vik Tara <[email protected]> wrote: > Hi Florent, > >> The base url retrive have to be "proxyied", have to be the same as the >> client see... >> > > Can you retrieve it from the header in the http request? Yep, I have done a try yesterday, but maybe too rapidly... I will done another try tomorrow... Thanks Vik, nice end of day ++ > > Regards > > > Vik > > On 04/15/2010 01:32 PM, Florent André wrote: >> Hi all, >> >> As I currently work on google's sitemap generation, I have to know the >> host name and path of the request. >> >> I have a look into inputs modules but I only see one that gave >> information >> about "lenya document" (required to have an uuid). >> >> In my use case, I don't have a lenya doc... Here comes the design main >> lines : >> >> - url finish with sitemap.xml (for example http://example.com/sitemap.xml >> , http://www.example.com/toto/foo/sitemap.xml) >> >> - publication's sitemap.XMAP intercept sitemap.xml ending and mount a >> sitemap.xmap in seo module >> >> - in seo module, I have >> -- a match on sitemap.xml >> -- a navigation module generator >> -- a navigationToSitemap transformer >> >> - into this transformer I have to know the entire url for generate a good >> sitemap.xml, I think to do this throw a<parameter name="baseUrl" >> value="{anInputModule:key}"> >> >> The base url retrive have to be "proxyied", have to be the same as the >> client see... >> >> Any help would be great appreciated, >> >> Have a good day >> ++ >> >> --------------------------------------------------------------------- >> To unsubscribe, e-mail: [email protected] >> For additional commands, e-mail: [email protected] >> > > > --------------------------------------------------------------------- > To unsubscribe, e-mail: [email protected] > For additional commands, e-mail: [email protected]