Re: Retrieve url path (host name plus path)

Florent André <[email protected]>
Newsgroups gmane.comp.cms.lenya.user
Message-ID <[email protected]>
Hi, just see your answer now... 

{request:requestURI} seems to be a VERY good solution !

Just have to try !

Thanks, cheers


On Thu, 15 Apr 2010 13:42:52 +0000, [email protected] wrote:
> Hi --
> 
> Have you checked out the Cocoon wiki on input modules? The request input

> module should do what you want, eg  
> {request:requestURI}?{request:queryString} would return the entire URL, 

> including request params. If the Apache proxy messes with the headers,
you
> 
> can always set ProxyPreserveHost On.
> 
> Ref: [ http://wiki.apache.org/cocoon/InputModules ] (and no, it's not  
> obsolete, although it says so at the top of the page).
> 
> Hope this helped,
> 
> /Petteri
> 
> On Apr 15, 2010 3:32pm, Florent André <[email protected]> 

> wrote:
>> Hi all,
> 
> 
> 
>> As I currently work on google's sitemap generation, I have to know the
> 
>> host name and path of the request.
> 
> 
> 
>> I have a look into inputs modules but I only see one that gave
>> information
> 
>> about "lenya document" (required to have an uuid).
> 
> 
> 
>> In my use case, I don't have a lenya doc... Here comes the design main
> 
>> lines :
> 
> 
> 
>> - url finish with sitemap.xml (for example
http://example.com/sitemap.xml
> 
>> , http://www.example.com/toto/foo/sitemap.xml)
> 
> 
> 
>> - publication's sitemap.XMAP intercept sitemap.xml ending and mount a
> 
>> sitemap.xmap in seo module
> 
> 
> 
>> - in seo module, I have
> 
>> -- a match on sitemap.xml
> 
>> -- a navigation module generator
> 
>> -- a navigationToSitemap transformer
> 
> 
> 
>> - into this transformer I have to know the entire url for generate a
good
> 
>> sitemap.xml, I think to do this throw a
>> value="{anInputModule:key}">
> 
> 
> 
>> The base url retrive have to be "proxyied", have to be the same as the
> 
>> client see...
> 
> 
> 
>> Any help would be great appreciated,
> 
> 
> 
>> Have a good day
> 
>> ++
> 
> 
> 
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