Re: [stack] adding construction to factor

John Nowak <[email protected]> wrote:
> I managed to add something like FP's construction form to Factor.

That looks nice, John.

> It
> treats stacks as if they were vectors in More's array theory, e.g. '5
> == {5}'.

Is "stacks" a typo here?

> I mentioned wanting to do this a few days ago, so I thought
> I'd share. Maybe it's useful.
> Here are a few of examples:
>    5 [( sq , dup , neg , drop ])  ==  25 { 5 5 } -5 { }
>    5 3 2@ [( + , - )]  ==  8 2
>    5 [( 5 + , 5 - )]  ==  10 0

Yes; that's nice and clear. It occurs to me that this is a parallel
execution operator.

> And here's the implementation:

Nice and terse. Very clear.

> - John

-Wm