Re: [stack] adding construction to factor

On Jan 4, 2009, at 11:16 AM, Christopher Diggins wrote:

> This looks like line noise to me. Either I'm dense, or the code could
> benefit from some comments.

I think the first half (up to and including the definition of  
'construct') should be fairly straightforward. If it helps, 'with- 
datastack' is the same as Joy's 'infra', the 'Narray' words group N  
elements on the stack into an array, and '[ ] each' is a gross way of  
putting all of the elements in an array onto the stack.

The second half just makes this:

    [( f g , h i )]

parse to this:

    { [ f g ] [ h i ] } construct

How it does that, I'm not exactly sure. It was much trial and error  
modifying the definition of '[' to suit my needs. I'd not written a  
parsing word in Factor before, so perhaps there's a better way to do it.

- John