Re: Luabind: C++ referenced variables;

hymedia wrote:
> I might have overlooked this  but I can’t find anything replicating this
> within the examples so far,
> 
> I m not crazy about using the properties. I d like to keep a C++
> structur as much as possible. So here is what I do:
> 
> .cpp
> 
> typedef unsigned int UInt;
> 
> class Test
> {
>       public:
>             Test(): val(0) {}
>             ~Test() {}
> 
>             UInt &Get() {return val;}
>             void Set(UInt in_val) {val = in_val;}
>       protected:
>             UInt val;
> };
> 
> Luabind
> 
>       module(in_lua)
>       [
>             class_<Test>("Test")
>             .def(constructor<>())
>             .def("Get", &Test::Get)
>             .def("Set", &Test::Set)
>       ];
>  
> .lua
> 
> myTest = Test();
> myTest:Set(1);
> myVal = myTest:Get();
> 
> Result:
> 
> myTest:Get(); assert: you are trying to use an unregistered type!
> 
> I know for sure the typedef is not an issue here, could have been a int,
> I have no doubts this have been addressed in the pass, but I could
> definitely use a hint.

The problem is that you are returning a reference to a builtin type.
There's no reasonable way to represent this reference in Lua, so luabind
doesn't accept it. I thought using the copy-policy: "copy(result)" would
work here, but it turns out that only works on class types.

If you can't change your function signature, your best bet is using
"tag_function<>" to bypass luabind signature deduction. Something like:

  def("Get", tag_function<UInt(Test const&)>(&Test::get))

-- 
Daniel Wallin
BoostPro Computing
http://www.boostpro.com

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