Re: I think I found a bug in Lua string.patterns, can anyone help see if it's true ?

Here is the pattern after `remove_re:gsub("\n", "\\n")` that I'm now 
looking at your tool:
====
\n\n\nCuentas Anuales%. Ejercicio %d+                                       
  +Pág%. %d+\n                     CUENTAS ANUALES DE LA ADMINISTRACIÓN 
GENERAL DE LA COMUNIDAD DE CASTILLA Y LEÓN%. EJERCICIO %d+\n\n\nEJECUCIÓN 
DEL PRESUPUESTO DE GASTOS DEL EJERCICIO %d+\nGASTOS POR 
APLICACIÓN\nADMINISTRACIÓN GENERAL[^\n]*\n[^\n]+\n\n[^\n]+\n\n
====

On Tuesday, May 12, 2026 at 2:21:24 PM UTC+2 Spar wrote:

> Correction. It's not actually the \n. It's because you used `[[ ]]` string 
> literals which works as C++ raw literals. They don't accept escapes.
>  
> So what actually happens can be described by my tool which doesn't accept 
> escapes too (i will fix it some day) :-)
>  
> https://gitspartv.github.io/lua-patterns/?pattern=%5B%5E%5Cn%5D*
> On May 12, 2026 at 15:20 +0300, Luiz Henrique de Figueiredo <
> [email protected]>, wrote:
>
> Try this simple pattern
>
> local remove_re = "Cuentas Anuales.-CREDITO%s+"
>
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>
>

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