Re: I think I found a bug in Lua string.patterns, can anyone help see if it's true ?

Hello Spar ! Your tool doesn't seem to interpret '[^\n]' properly:
```
[^...]Inverse set.Matches any character except:
\Character.Doesn't match "\" literally.
nCharacter.Doesn't match "n" literally.
*Quantifier (zero or more).Allows to match the pattern zero or more times. 
This will match the longest sequence.
```

On Tuesday, May 12, 2026 at 2:35:14 PM UTC+2 Domingo Alvarez Duarte wrote:

> Here is the pattern after `remove_re:gsub("\n", "\\n")` that I'm now 
> looking at your tool:
> ====
> \n\n\nCuentas Anuales%. Ejercicio %d+                                     
>     +Pág%. %d+\n                     CUENTAS ANUALES DE LA ADMINISTRACIÓN 
> GENERAL DE LA COMUNIDAD DE CASTILLA Y LEÓN%. EJERCICIO %d+\n\n\nEJECUCIÓN 
> DEL PRESUPUESTO DE GASTOS DEL EJERCICIO %d+\nGASTOS POR 
> APLICACIÓN\nADMINISTRACIÓN GENERAL[^\n]*\n[^\n]+\n\n[^\n]+\n\n
> ====
>
> On Tuesday, May 12, 2026 at 2:21:24 PM UTC+2 Spar wrote:
>
>> Correction. It's not actually the \n. It's because you used `[[ ]]` 
>> string literals which works as C++ raw literals. They don't accept escapes.
>>  
>> So what actually happens can be described by my tool which doesn't accept 
>> escapes too (i will fix it some day) :-)
>>  
>> https://gitspartv.github.io/lua-patterns/?pattern=%5B%5E%5Cn%5D*
>> On May 12, 2026 at 15:20 +0300, Luiz Henrique de Figueiredo <
>> [email protected]>, wrote:
>>
>> Try this simple pattern
>>
>> local remove_re = "Cuentas Anuales.-CREDITO%s+"
>>
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>> .
>>
>>

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